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Factor completely 49x*2 − 81.
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Diffrence of squares \[\huge~\rm~\sqrt{49x^2}-\sqrt{81}\]
Try , since both coefficients are squares, and a minus sign.....( ( a + b) * ( a - b)
@pooja195 that setup is much more easier.
What set up?
When you square root the numbers instead of trying to factor them. Some people don't think of square rooting the numbers.
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Right :) thanks ^-^ @DanJS 's work is helpful too since it belongs in that form :)
is it (7-9)*2
I think that is what it looks like, if you have perfect squares a and b \[a^2*x^2 - b^2 = (a+b)*(a-b\]
sorry (ax - b)*(ax+b)
distribute backwards and check, it works out both ways
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No rember the x's...u have it some what correct (7x+9) (7x-9) We need a positive and a negative statement
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