What are the coordinates of the vertex for f(x) = 2x2 + 4x + 9? (−2, 4) (−1, 7) (1, 15) (2, 9)
formula to find x coordinate of vertex \[\huge\rm x=\frac{ -b }{ 2a }\]
then substitute all x in f(x) equation for its value to find y-coordinate of vertex
what do i put for the a and b?
a=leading coefficient b=middle term \[\huge\rm \color{reD}{A}x^2+\color{blue}{B}x+C=0\]
ok thank you
do i leave the negative sign in front of the b even when it's a positive?
yes b is positive but negative is in the formula so that stays there
so it would be \[x=\frac{ -4 }{ 2(2)}\]?
yep right
so -4/4 and i would just divide it and it would come out as -1 right?
yes that's x-coordinate
how do i find the y-coordinate now?
now to find y -coordinate substitute x for -1 \[\rm \color{reD}{x=-1}\] \[\huge\rm 2\color{reD}{x}^2+4\color{red}{x}+9=0\]
so the y-coordinate would be 3? (-1,3)?
mhm
when you take square of negative number you will get positive number
how do i do that
\[\huge\rm 2\color{reD}{(-1)}^2+4\color{red}{(-1)}+9=0\] now solve (-1)^2 is same as -1 times -1 = ?
so 1?
yes -1 times -1 = 1 (-1)^2=1 so solve \[\huge\rm 2\color{reD}{(1)}+4\color{red}{(-1)}+9=?\]
oh so (-1,7)
yep
could you help me out with another one
@Nnesha
i'll try
What is the equation of the quadratic graph with a focus of (5, −1) and a directrix of y = 1? f(x) = −one fourth (x − 5)2 + 1 f(x) = one fourth (x − 5)2 + 1 f(x) = −one fourth (x − 5)2 f(x) = one fourth (x − 5)2
@Nnesha ?
well not sure about this need to review this stuff hmm
sorry
its fine. i got it Cx thank you tho !
np
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