Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

The base of a solid in the xy-plane is the circle x2 + y2 = 16. Cross sections of the solid perpendicular to the y-axis are equilateral triangles. What is the volume, in cubic units, of the solid?

OpenStudy (danjs):

Do you know what the solid is?

OpenStudy (anonymous):

no I don't know how to start this problem

OpenStudy (danjs):

|dw:1438722075391:dw|

OpenStudy (danjs):

They gave you x^2 + y^2 = 16 = r^2 That is a circle radius 4 centered at the origin, in the XY-plane...

OpenStudy (danjs):

you recognize that?

OpenStudy (anonymous):

yes

OpenStudy (danjs):

|dw:1438722233544:dw|

OpenStudy (danjs):

bad drawing, but that is a slice of the shape perpendicular to the Y axis

OpenStudy (danjs):

saying it is equilateral, means that is a Right Circular Cone

OpenStudy (anonymous):

okay so you need the volume formula for a right circular cone correct?

OpenStudy (danjs):

yes, just remember, it is the area of the base times 1/3 the height

OpenStudy (anonymous):

ok

OpenStudy (danjs):

need to figure the height

OpenStudy (danjs):

Loooking at the cross section at the XZ axis head on... the base is 2 times the radius

OpenStudy (danjs):

|dw:1438722512573:dw|

OpenStudy (danjs):

THe y axis is pointing out from the page, that is the origin

OpenStudy (danjs):

Equilateral triangle, so the diagonals are the same as the base, 2 radiuses

OpenStudy (danjs):

radii

OpenStudy (danjs):

r=4, use pythagorean theorem to figure the height

OpenStudy (danjs):

|dw:1438722659628:dw|

OpenStudy (danjs):

You get it all?

OpenStudy (anonymous):

yes so far

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!