Question

Abel uses a probability simulator to roll a six-sided number cube 100 times and to flip a coin 100 times. The results of the experiment are shown below:


Number on the Cube Number of Times Rolled
1 12
2 18
3 30
4 22
5 10
6 8


Heads Tails
34 66


Using Abel's simulation, what is the probability of rolling a 2 on the number cube and the coin landing on tails?
fraction 84 over 10,000
fraction 1,188 over 10,000
fraction 18 over 100
fraction 66 over 100

Answer 1

can i get help by help step

Answer 2

@Mertsj can you help

Answer 3

Probability of A and B for independent events is P(A) x P(B)

Answer 4

36*66?

Answer 5

2376/2 = 1188? @Mertsj

Answer 6

What is the probability of a 2?

Answer 7

100/2?

Answer 8

@Mertsj

Answer 9

am i on the right track

Answer 10

@kropot72 am i on the right

Answer 11

The probability of rolling a 2 is given by:
\[\large P(2)=\frac{number\ of\ 2s\ rolled}{total\ rolls}\]

Answer 12

ok @kropot72

Answer 13

1188/10000 @kropot72

Answer 14

@steffie84 How did you get that?

Answer 15

66*34/2*100*100

Answer 16

@kropot72

Answer 17

Not really. What is the probability of rolling a 2 (using the equation in my first post here)?

Answer 18

total roll is 100?

Answer 19

@kropot72 am not sure what

Answer 20

The number 2 came up 18 times in a total of 100 rolls.

Answer 21

@kropot72 just saw what you are talking about

Answer 22

18/100

Answer 23

Correct. The probability of tails is found from:
\[\large P(tails)=\frac{number\ of\ tails}{total\ flips}\]

Answer 24

66/100

Answer 25

Correct again. Therefore as @Mertsj told you, the required probability is given by:
\[\frac{18}{100}\times\frac{66}{100}=you\ can\ calculate\]
Hint: Do not simplify the result of your calculation.

Answer 26

1188

Answer 27

10000

Answer 28

So the result is
\[\large \frac{1188}{10000}\]

Answer 29

yes

Answer 30

@kropot72 @Mertsj thanks

Answer 31

You're welcome :)