Question

help please.
Find (f + g)(x), (f - g)(x), (f . g)(x), and (f/g)(x) for each f(x) and g(x).

1. f(x) = a^2 - 1 , g(x) = a/(a + 1)

(f+g)(x)
(f-g)(x)
and
(f/g)(x)

Answer 1

(f+g)(x) means to add f(x) and g(x)

Answer 2

(f-g)(x) means to take away g(x) from f(x)
or just write f(x)-g(x)

Answer 3

(f/g)(x) means to write f(x)/g(x)

Answer 4

ok i have a question

Answer 5

what is wrong with this picture \[f(x) = a^2 - 1\]

Answer 6

im lost

Answer 7

it is a constant function satellite :p
example:
\[f(x)=2 \\ g(x)=3+x \\ \text{ then } (f+g)(x)=2+(3+x)=5+x \\ \text{ also } (f-g)(x)=2-(3+x)=-x-1 \\ \text{ and } (\frac{f}{g})(x)=\frac{2}{3+x}\]

Answer 8

me too
if you have a function of x, it should have an x in it

Answer 9

whats going on?

Answer 10

well are your functions really f(x)=a^2-1 and g(x)=a/(a+1) ?

Answer 11

don't know
does it really say
\[f(x)=a^2-1\] or is it
\[f(x)=x^2-1\]

Answer 12

freckles, yes.

Answer 13

what it says is what it is. I'm just not understanding how to solve it.

Answer 14

whatever they are
just add f(x) and g(x) to find (f+g)(x)

Answer 15

okay

Answer 16

have you found (f+g)(x)?

Answer 17

nope I've been trying but i don't know what I'm doing

Answer 18

do you know how to add f(x) and g(x)
that is do you know how to add a^2-1 and a/(a-1) ?

Answer 19

no

Answer 20

\[(f+g)(x)=f(x)+g(x) \\ =a^2-1+\frac{a}{a-1}\]
that is it unless you are asked to combine the fractions

Answer 21

no i wasn't.

Answer 22

try this one:
\[(f-g)(x)=f(x)-g(x)\]

Answer 23

no clue

Answer 24

f(x)=a^2-1
and g(x)=a/(a-1)
all you have to do is replace f(x) with a^2-1
and g(x) with a/(a-1)

Answer 25

what exactly am i doing with this? and should the answer be a equation?

Answer 26

i understand none of this and it gets frustrating

Answer 27

the expression should be an expression of x
in this case the expression of x is a constant expression since the expression is really an expression in terms of a

Answer 28

I'm attempting to follow

Answer 29

pretend f(x)=5 and g(x)=6
(f+g)(x)=f(x)+g(x)=5+6=11
you are just replacing f(x) with 5 and g(x) with 6
(f-g)(x)=f(x)-g(x)=5-6=-1
I just replaced f(x) with 5 and g(x) with 6
(f/g)(x)=f(x)/g(x)=5/6
again I just replaced f(x) with 5 and g(x) with 6

Answer 30

(f*g)(x)=f(x)*g(x)=5*6=30
again I just replaced f(x) with 5 since in my example I let f(x)=5
and I just replaced g(x) with 6 since in my example I let g(x)=6

Answer 31

ok

Answer 32

ok now you try finding (f-g)(x) for your f(x) and g(x)

Answer 33

remember (f-g)(x) is the same as f(x)-g(x)

Answer 34

just replace f(x) with a^2-1
and g(x) with a/(a-1)