Question

Max observes the zoo and the library from a helicopter flying at a height of 200 times square root of 3 feet above the ground, as shown below:

Answer 1

What is the distance between the zoo and the library?

Answer 2

90/?

Answer 3

i think first you need to find hypotenuse side of right triangle by using \[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]

Answer 4

blue line = hypotenuse

Answer 5

use sin function \[\rm sin 60= \frac{ opposite }{ hypotenuse }\]

Answer 6

oh i got the answer but ill wait for nnesha :)

Answer 7

@Nnesha 400 right?

Answer 8

Hoe did you get that answer?

Answer 9

oh so you saw the answer huh? :/ lol

Answer 10

how* SORRY

Answer 11

http://openstudy.com/study#/updates/53bc4175e4b0bbb79bdb2c9a

Answer 12

that should help

Answer 13

and there are a few more questions that i think you didnt post yet but are yours?

Answer 14

if it helped the medal will be waiting for me :) xD

Answer 15

.

Answer 16

what @nnesha?

Answer 17

what ? let me know if you still don't get anything :=)

Answer 18

are you studying trigonometry (using sin and cos) or
are you supposed to be using "special triangles" in this case, 30-60-90 triangles?

Answer 19

@phi Im studying trig

Answer 20

in that case, use nnesha's picture
notice in the red triangle,
\[\tan 60 = \frac{200\sqrt{3}}{x} \]
tan 60 is one of those values you should memorize. it is sqr(3)
thus
\[ \sqrt{3}= \frac{200\sqrt{3}}{x} \\ x= 200\]

now for the large triangle
\[ \tan 30 = \frac{200\sqrt{3}}{x} \]
tan 30 = 1/sqrt(3)
so you have
\[ \frac{1}{\sqrt{3} }= \frac{200\sqrt{3}}{x} \]
hopefully you find x= 600

thus the bottom of the big triangle is 600
the distance from G to zoo is 200

the difference is the distance from the zoo and library.