Question

PLEASE HELP!!!!! MEDAL AND FAN!!!!!

26. Give the center coordinates (x,y) of the circle:
(x + 3)2 + (y - 4)2 = 36

27. Give the radius of the circle:
(x + 3)2 + (y - 4)2 = 36

28. Give the center coordinates (x,y) of the circle:
(x + 1)2 + (y - 6)2 = 2.25

29. Give the radius of the circle:
(x + 1)2 + (y - 6)2 = 2.25

Answer 1

@satellite73

Answer 2

this is 26? \[(x+3)^2+(y-4)^2=36\]

Answer 3

But how do I solve it?

Answer 4

center of the circle has got to do with the 3 and the 4

Answer 5

when the center shift left it becomes (x+h)^2 and (x-h)^2 when it shifts right, same with the y axis

Answer 6

wait would the answer to number 26 be -3,4

Answer 7

yes

Answer 8

now for the radius you know the circle comes in this package \[(x+3)^2+(y-4)^2=36\]which is equivalent to \[(x+h)^2+(y-k)^2=r^2\]

Answer 9

Would it be 6?

Answer 10

yes

Answer 11

now use the same method for 28 & 29

Answer 12

So 28 is -6,1

Answer 13

And 29 is 1.5

Answer 14

Is tha correct?

Answer 15

*that

Answer 16

no and yes

Answer 17

you swapped the x and y position for 28

Answer 18

So it's 1,-6

Answer 19

yes

Answer 20

-1,6

Answer 21

Oh okay thanks for you help.

Answer 22

not -6,1

Answer 23

yw