Question

given the following quadratic inequality solve.
x^2+17x+72>0

Answer 1

Raise x to the 2nd power

Answer 2

(x2 + 17x) + 72 > 0

Answer 3

Simplify x2+17x + 72

Answer 4

Factor x2+17x+72

Answer 5

The first term is, x2 its coefficient is 1 .
The middle term is, +17x its coefficient is 17 .
The last term, "the constant", is +72

Answer 6

is it x<-9 and x>-8 or is it x<-9 or x>-8?

Answer 7

Step-1 : Multiply the coefficient of the first term by the constant 1 • 72 = 72

Step-2 : Find two factors of 72 whose sum equals the coefficient of the middle term, which is 17 .

Answer 8

-72 + -1 = -73
-36 + -2 = -38
-24 + -3 = -27
-18 + -4 = -22
-12 + -6 = -18
-9 + -8 = -17
-8 + -9 = -17
-6 + -12 = -18
-4 + -18 = -22
-3 + -24 = -27
-2 + -36 = -38
-1 + -72 = -73
1 + 72 = 73
2 + 36 = 38
3 + 24 = 27
4 + 18 = 22
6 + 12 = 18
8 + 9 = 17 That's it

Answer 9

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 8 and 9
x2 + 8x + 9x + 72

Answer 10

Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x+8)
Add up the last 2 terms, pulling out common factors :
9 • (x+8)

Answer 11

Step-5 : Add up the four terms of step 4 :
(x+9) • (x+8)
Which is the desired factorization

Answer 12

(x + 9) • (x + 8) > 0

Answer 13

Solve (x+9)•(x+8) > 0

Answer 14

there

Answer 15

i know i solved it i just need to know if its x<-9 AND x>-8 or is it x<-9 OR x>-8?

Answer 16

oh

Answer 17

well my answer tells u c;brb