Question

The circle (x−2)^2+(y−3)^2=4 can be drawn with parametric equations.
Assume the circle is traced clockwise as the parameter increases.
If x=2+2cos(t)

then y =

Answer 1

(2 + 2 cos (t) - 2)² + (y - 3)² = 4
4 cos² t + (y - 3)² = 4
Solve for y

Answer 2

5-4cos(t) i got this but it wasn't correct still

Answer 3

can u help?

Answer 4

(y - 3)² = 4 - 4 cos² t
(y - 3)² = 4(1 - cos² t)
\[y - 3 = \pm \sqrt{4(1-\cos^2 t)}\]
\[y = 3\pm 2\sqrt{(1-\cos^2 t)}\]

Answer 5

awesome thank u for ur help

Answer 6

np