Question

Need Help! How do you solve for (3/7)^7/3 to be in fraction form?

Answer 1

Is the question
\(\Large \frac{(\frac{3}{7})^7}{3}\)
or is it
\(\Large (\frac{3}{7})^\frac{7}{3}\) ?
In any case, use
\((\frac{A}{B})^X=\frac{A^X}{B^X}\) and
\(M^\frac{x}{y}=\sqrt[y]{M^x}\)
to help you.

Answer 2

It's the second one!

Answer 3

So if I were using the first method, it would be something like: 3^7/3 all over 7^7/3 ?

Answer 4

But what would I do after that?

Answer 5

@mary_am
Please remember the priority of operations require that exponentiation is before multiplication and division, so use brackets as required.
\(\Large (\frac{3}{7})^\frac{7}{3}\) is written (3/7)^(7/3) to avoid further confusion.

Answer 6

"So if I were using the first method, it would be something like: 3^7/3 all over 7^7/3 ? "
probably meant
= ( 3^(7/3) ) / ( 7^(7/3) )
Yes written that way would be correct.

Answer 7

Okay, and then what would happen?

Answer 8

Then you would use the second rule to make it a simple fraction.