Question

Giving medal to whoever can help?

To open these doors, you must match the number and type of solutions for the following two functions in standard form.
f(x) = x2 + 6x – 16
g(x) = x2 +6x + 1
Match the following descriptions of the solutions to each of the functions above.
Hint: they each have their own match.

Two real irrationals solutions
Two real rationals solutions
After matching these functions, explain to Professor McMerlock how you know these functions meet each condition. Remember, he is a professor, so use complete sentences.

Answer 1

anyone?

Answer 2

please...

Answer 3

if discriminant D=b^2-4ac>0 and a perfect square,then roots are real ,rational and different.
if D>0 and not a perfect square then roots are real and irrational.

Answer 4

woah i didn't quite understand that..

Answer 5

@surjithayer

Answer 6

for first D=b^2-4ac=6^2-4(1)(-16=36+64=100=10^2
what can you say now?

Answer 7

correction
d=6^2-4(1)(-16)=36+64=100=10^2

Answer 8

I'm sorry i thought you were suppose to just match the two top ones with the bottom and then explain why each one is which..

Answer 9

i have solved for f(x)

Answer 10

oh ok so the answer for the f(x) is d=6^2-4(1)(-16)=36+64=100=10^2

Answer 11

explanation i have given above ,you have to see.
you see it is positive and a perfect square.

Answer 12

what about for g(x)?

Answer 13

sorry I'm bothering, ill give you the medal just please help with that last part..

Answer 14

@surjithayer

Answer 15

?

Answer 16

can someone at least just explain the bottom half for me?