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Mathematics 8 Online
OpenStudy (anonymous):

help!!!!!!!!!!!!!!!!!!

OpenStudy (anonymous):

Olivia rolls two fair number cubes numbered from 1 to 6. She first defines the sample space as shown below: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6) (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6) (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6) (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) Based on the sample space, what is the probability of getting a total of 10?

OpenStudy (anonymous):

First off, count how many ordered pairs there are in total

OpenStudy (anonymous):

Then, count how many of those ordered pairs have a sum of 10

OpenStudy (anonymous):

Lastly, write it as a fraction and simplify

OpenStudy (anonymous):

can you help me

OpenStudy (anonymous):

Sure!

OpenStudy (mathstudent55):

How many outcomes have a sum of 10? \((1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)\) \( (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)\) \( (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)\) \( (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), \color{red}{(4, 6)}\) \( (5, 1), (5, 2), (5, 3), (5, 4), \color{red}{(5, 5)}, (5, 6)\) \( (6, 1), (6, 2), (6, 3), \color{red}{(6, 4)}, (6, 5), (6, 6)\)

OpenStudy (anonymous):

There are 36 ordered pairs total

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

3 of which have a sum of 10

OpenStudy (anonymous):

\[\frac{ 3 }{ 36 }\]

OpenStudy (anonymous):

Simplify that and you have your answer

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

You're welcome!

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