help!!!!!!!!!!!!!!!!!!
Olivia rolls two fair number cubes numbered from 1 to 6. She first defines the sample space as shown below: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6) (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6) (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6) (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) Based on the sample space, what is the probability of getting a total of 10?
First off, count how many ordered pairs there are in total
Then, count how many of those ordered pairs have a sum of 10
Lastly, write it as a fraction and simplify
can you help me
Sure!
How many outcomes have a sum of 10? \((1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)\) \( (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)\) \( (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)\) \( (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), \color{red}{(4, 6)}\) \( (5, 1), (5, 2), (5, 3), (5, 4), \color{red}{(5, 5)}, (5, 6)\) \( (6, 1), (6, 2), (6, 3), \color{red}{(6, 4)}, (6, 5), (6, 6)\)
There are 36 ordered pairs total
yes
3 of which have a sum of 10
\[\frac{ 3 }{ 36 }\]
Simplify that and you have your answer
thanks
You're welcome!
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