Question

I LOVE MATH!

Answer 1

Lol you love math? :P

Answer 2

I'm factoring out greatest common factors for this one:\[6x^3-8x^2+10x\]\[2x(3x^2-4x+5)\] That's what I got.. Is it right?

Answer 3

Yeah I definitely do. Can't you tell? lol;)

Answer 4

Perfect! and oh of course ;P

Answer 5

Lol. yay haha. Factor by grouping: \[3x^2-6xy-4x+8y\]

Answer 6

I haven't got my answer yet but I'm working on it lol.

Answer 7

Tell me when you do :D

Answer 8

Ok, well for the first half I have
3x(x-2y)..... Blah...

Answer 9

Perfect....and the next half?

Answer 10

For the second half.. I have:
4(-x+2y)

Answer 11

Please tell me it's right lol.

Answer 12

WAIT.

Answer 13

LOL.

Answer 14

STOP>

Answer 15

I think I know what you're gonna say haha!

Answer 16

WAIT. PAUSE LOL>

Answer 17

Lol I'll wait ;P

Answer 18

It's the same thing hahaa;)

Answer 19

-4(x-2y)

Answer 20

There we go :P

But what next? O.o

Answer 21

Idk you tell me haha

Answer 22

Lol so we have

\[\large 3x(x - 2y) - 4(x - 2y)\]

Since they both have a (x - 2y) in common...we factor that out...and write this as

\[\large (3x - 4)(x - 2y)\]

Answer 23

Ohh yeah. Duhh I forgot lol. Thanks for the reminder.

Answer 24

Haha oh of course that's what I'm here for ;P

Answer 25

Hhaa, lol. I honestly can't explain how happy I am that you're on and you could help me LOL!

Answer 26

Well I had to cuz I love you remember <3 ;D lol

No I like helping you cuz you dont bug me :P

Answer 27

\[x^2-5x+4\]
So I'm supposed to be factoring this out... Haven't done it but I'll give it a shot lol. Ohh yeah hhaa. Duhh<3 Are you sure I don't? I feel like I am haha.

Answer 28

I'd set it to 0 right?

Answer 29

Lol nope you do all the work and I sit here and wait ;P

And yes set it equal to 0

Answer 30

Hha, ok lol. Ok: So I have this so far: \[\frac{ -(-5)\pm \sqrt{(-5)^2-4(1)(4)} }{ 2(1) }\]

Answer 31

mmhmm....continue :)

Answer 32

I got prime. Is it right?

Answer 33

Huh?

\[\large \frac{5 \pm \sqrt{9}}{2}\]

is what I get

Answer 34

Well 4*-4 = -16
And -5*-5=25 and I added that and got 41...

Answer 35

25 + -16 would be subtraction :)

Answer 36

Well, I thought like if there's something like this:
25-(-16)... You would add...

Answer 37

OH WAIT. THAT'S FOR ADDITION right?

Answer 38

Or something idk...

Answer 39

No you are correct...if it were 25 - (-16) it would be 25 + 16

however here we have

\[\large \sqrt{(-5)^2 - 4(1)(4)}\rightarrow \sqrt{25 - (16)} = \sqrt{9}=3\]

Answer 40

Ok, I see where you're getting that from..

Answer 41

Good ^_^

so then yes we have

\[\large \frac{5 \pm 3}{2}\]

Answer 42

So the -4 is positive right? I'd read the 4 as a positive sign and the negative sign would be read to subtract right?

Answer 43

I got 4,1

Answer 44

Well just take it part by part...

\[\large \sqrt{(-5)^2 - \color\red{(4(1)(4))}}\]

focus on on the red first, dont even worry about that ''-" sign right now

\[\large \sqrt{25 - (16) }\]

Answer 45

And yes 4 and 1 would be correct

So now...we know these are the roots of your polynomial

We write them as

\[\large (x - 4)(x-1) = 0\]

And that is the factored form of it

"why did it change to both being "minus"?

Well because look at the equation...equal to 0

we want to be able to plug in either 4 or 1 into an equation and get 0....thus...we have that :)

Answer 46

Ok, makes total sense lol.

Answer 47

does it really?

Answer 48

Yeah I think haha. I may say something stupid right now cuz it's 1:31am..

Answer 49

Lol same here :P

Answer 50

I'm a little cranky cuz I only got 3hrs of sleep last night. Haha. awesome!

Answer 51

Uh oh...get some sleep love :P

Answer 52

Ik, but it's hard in cramming this homework and a final exam on campus tomorrow..

Answer 53

If a polynomial does not factor out it'd be a prime right? cuz I'm asked to factor out
81x^2-1
But I get:
1(81x^2-1)

Answer 54

right, its just prime if nothing can be taken out

Answer 55

okie. At least I got the last question right haha. There's more but I'll finish everything up tomorrow once I get up in like 3hrs... Goodnight! Sleep tight;)

Answer 56

Sleep tight hun ;)

Answer 57

Hha, thanks lol ;) Anywho.. Audios!