Question

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Answer 1

@bradely

Answer 2

u there

Answer 3

f(x) = x3 + 4x2 + x – 6 .
Last value is not 6 i think it is -6
(x -1)(x +2)(x +3) x = –3, x = 1, x = –2
So option D is correct

Answer 4

What are the coordinates of the turning point for the function f(x)=(x+3)^3+1?
(-3,-1)
(-3,1)
(3,-1)
(3,1)

Answer 5

f(x)=(x+3)^3+1
Take derivative then equal to zero to get turning point please see in example
http://www.mathskey.com/question2answer/22377/function-y-x-1-2-e-2x

Answer 6

didn't learn deritive what's the answer so i can work backward

Answer 7

f(x) = (x+3)^2 +1
Take derivative
f'(x) = 2(x+3)
f'(x) = 0
2(x+3) =0
x = -3

f(-3) = (-3+3)^2 +1
=1
(-3,1) is the turning point

Answer 8

What is the remainder when (3x^4+2x^3-x^2+2x-14) / (x+2)?
0
5
10
15

Answer 9

Substitute x = -2 in 3x^4+2x^3-x^2+2x-14
to get remainder

Answer 10

10?

Answer 11

correct

Answer 12

what is the quotient (2x^2 +12x+18)/(x+3)?
2x+6
2x-6
2x+4
2x-4, r=1

Answer 13

(2x^2 +12x+18)/(x+3)
Common the two
2(x^2 +6x+9)/(x+3)
Find the factor of x^2 +6x+9
x^2 +6x+9=(x+3)^2
2(x^2 +6x+9)/(x+3) = 2(x+3)^2/(x+3)
2(x+3)
2x+6

Answer 14

Using synthetic division, what is the quotient (3x^3+4x -32)/ (x-2)?
3x^2 +6x-16
3x^2-6x +16
3x^2+6x+16
3x^2-6x-16 +1/(x-2)

Answer 15

(3x^3+4x -32)/ (x-2)
Please see in below link you can understand
http://www.mathskey.com/question2answer/18096/use-synthetic-division-find-the-quotient-and-the-remainder

Answer 16

Thats it for now