HELP PLEASE!!! LITERAL EQUATIONS!!

Question

cookie_monster · Answer

The area of this figure can be found by the formula A = (wh) + 0.5(bh). If Marcie wants the total area to be larger than a specified value, she can use the formula A > (wh)+ 0.5(bh). Rewrite this formula to solve for b. Show all steps in your work.

cookie_monster · Answer

A > (wh)+0.5(bh)
                                                 A(wh) > 0.5(bh)
                                                 A(wh) * 2 > (bh)
                                                 A(wh) * 2/h > (b)
This the answer I got, but I have a feeling it's not correct.

nnesha · Answer

wh is adding with .5(bh)
so to cancel out wh from right you need to do opposite of addition

nnesha · Answer

multiplication <----opposite ----> division

nnesha · Answer

??

cookie_monster · Answer

Ok, so A - (wh) > 0.5(bh)

cookie_monster · Answer

What I really need to know is how I deal with the 0.5. That's what's getting and it's on multiple problems

cookie_monster · Answer

@Nnesha You there?

nnesha · Answer

oops oh yea 
so that's right now multiply both sides by 2 
remember .5 =1/2 so you can change it to fraction  $$\huge\rm A-wh>\frac{ bh }{ 2 }$$

cookie_monster · Answer

So the answer would be 
$$b < A - (wh) * 2 \div h$$

nnesha · Answer

multiply left side by 2 so 
2(a-wh)

nnesha · Answer

$$\huge\rm \frac{ 2(A-wh) }{ h }>b$$ multiply whole thingy not just wh

nnesha · Answer

now distribute parentheses by 2

cookie_monster · Answer

Ah ok. Thank you so much!! I understand now.

nnesha · Answer

my pleasure