Question

Find the vertical asymptotes, if any, of the graph of the rational function. Show your work.


f(x) =

Answer 1

@dan815 @abb0t

Answer 2

@DullJackel09 @TheRaggedyDoctor

Answer 3

@Luigi0210

Answer 4

@sammixboo

Answer 5

@poopsiedoodle @pooja195

Answer 6

plz help me id understand this trickery at all

Answer 7

@dan815

Answer 8

okay pick a rational function and tell me

Answer 9

what is a rational function lol

Answer 10

haha

Answer 11

Consider where the fraction is not defined. When you have a fraction, what is that famous number you cannot divide by?

Answer 12

0 lol i think or im stupid lol

Answer 13

You aren't stupid. And that is an awesome answer because it is true.
So when is your fraction's bottom zero?
For what value of x, do you have x-1 is zero?

Answer 14

good question idk how to answer them

Answer 15

what number can you take away 1 from and have zero?

Answer 16

is 5-1 zero?
is 2-1 zero?

Answer 17

no 1-1 is 0

Answer 18

yes x-1=0 has solution x=1
you could have also just added 1 on both sides

Answer 19

true ok i get it somewhat now

Answer 20

ok so if i was to answer this question then how would i phrase this

Answer 21

x=1 is your vertical asymptote
though if there was a factor of x-1 on top then it could possibly be a hole (but you do not have that here)
that is f(x)=(x-1)/(x-1) has a hole at x=1 (not a vertical asymptote)
that is f(x)=x(x-1)/(x-1) also has a hole at x=1
but g(x)=(x-1)/(x-1)^2 has a vertical asympote at x=1 since it has more (x-1)'s on bottom then on top

Answer 22

i hate math so bad lol good thing this is my lsast math class lol thnx for your help

Answer 23

np

Answer 24

thank you to dan