so it was the one with the twos right on the left side
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OpenStudy (freckles):
both x and y are -sqrt(2)/2 there
\[\cot(-\frac{5\pi}{4})=-\cot(\frac{5\pi}{4})=- \frac{\cos(\frac{5\pi}{4})}{\sin(\frac{5\pi}{4})}=-\frac{\frac{-\sqrt{2}}{2}}{\frac{-\sqrt{2}}{2}}\]
OpenStudy (freckles):
you can simplify that
OpenStudy (anonymous):
smh how do i simplify that ?
OpenStudy (freckles):
what is 5/5 =?
6/6=?
3/3=?
OpenStudy (anonymous):
1
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OpenStudy (freckles):
12/12=
-12/-12=?
OpenStudy (freckles):
yes
OpenStudy (freckles):
so you have -1
because there is negative in front of that mess
OpenStudy (anonymous):
right
OpenStudy (anonymous):
@phi
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OpenStudy (anonymous):
@dan815
OpenStudy (freckles):
@tazmaniadevil did you have another question
OpenStudy (anonymous):
yes is -1 my answer
Nnesha (nnesha):
\(\color{blue}{\text{Originally Posted by}}\) @freckles
so you have -1
because there is negative in front of that mess
\(\color{blue}{\text{End of Quote}}\)
\(\color{blue}{\text{Originally Posted by}}\) @Tazmaniadevil
yes is -1 my answer
\(\color{blue}{\text{End of Quote}}\)