Ask
your own question, for FREE!
Mathematics
9 Online
OpenStudy (anonymous):
Using the completing-the-square method, rewrite f(x) = x2 + 10x + 7 in vertex form
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@ganeshie8 @dan815 @Kainui @Michele_Laino @DanJS
OpenStudy (michele_laino):
hint:
we can add and subtract 25, so we can write this:
\[\Large \begin{gathered}
f\left( x \right) = {x^2} + 10x + 7 = \hfill \\
\\
= {x^2} + 10x + 25 - 25 + 7 \hfill \\
\end{gathered} \]
OpenStudy (anonymous):
What does that do? confused
OpenStudy (michele_laino):
we have:
\[\Large {x^2} + 10x + 25 = {\left( {x + 5} \right)^2}\]
am I right?
OpenStudy (anonymous):
f(x)=(x+5)^2-18
f(x)=(x+10)^2+25
f(x)=(x+5)^2+7
f(x)=(x+5)^2
Those are my options btw
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (michele_laino):
so, what is the right option? Please look at my second hint
OpenStudy (anonymous):
I'd say B
OpenStudy (michele_laino):
sorry, it is not B
OpenStudy (michele_laino):
hint:
\[\Large \begin{gathered}
f\left( x \right) = {x^2} + 10x + 7 = \hfill \\
\hfill \\
= {x^2} + 10x + 25 - 25 + 7 = \hfill \\
\hfill \\
= {x^2} + 10x + 25 - 18 \hfill \\
\end{gathered} \]
OpenStudy (michele_laino):
please keep in mind that:
\[\Large {x^2} + 10x + 25 = {\left( {x + 5} \right)^2}\]
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
So its A?
OpenStudy (michele_laino):
yes! that's right!
OpenStudy (anonymous):
Thank you!!
OpenStudy (michele_laino):
:)
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
clllaaaaaire:
CLOSED
2 weeks ago
0 Replies
0 Medals