Question

Find the values of x so that the series below converges. (((x+8)^(n))/(2^n)) please help find the interval. goes to INF and n=0

Answer 1

Is this the equation?
\[
a_n=\frac{(x+8)^n}{2^n}
\]

Answer 2

yes

Answer 3

What is the required limit?

Answer 4

I'm looking to find the values of x so that the series below converges. (the interval it does

Answer 5

limit is n=0

Answer 6

to INF

Answer 7

does that makes sense can u help?

Answer 8

So the question is find x such that:
\[
\lim_{n\to0}\frac{(x+8)^n}{2^n}=\infty
\]

Answer 9

no it has the simga logo in front of the fraction with a INF aboe th sigma and a n=0 below

Answer 10

\[\sum_{n=0}^{INF}\]

Answer 11

Find such x such that:
\[
\sum_{n=0}^\infty\frac{(x+8)^n}{2^n}=\infty
\]