Find the values of x so that the series below converges. (((x+8)^(n))/(2^n)) please help find the interval. goes to INF and n=0

Question

Find the values of x so that the series below converges.  (((x+8)^(n))/(2^n)) please help find the interval.   goes to INF and n=0

thomas5267 · Answer

Is this the equation?
$$
a_n=\frac{(x+8)^n}{2^n}
$$

anonymous · Answer

yes

thomas5267 · Answer

What is the required limit?

anonymous · Answer

I'm looking to find  the values of x so that the series below converges. (the interval it does

anonymous · Answer

limit is n=0

anonymous · Answer

to INF

anonymous · Answer

does that makes sense can u help?

thomas5267 · Answer

So the question is find x such that:
$$
\lim_{n\to0}\frac{(x+8)^n}{2^n}=\infty
$$

anonymous · Answer

no it has the simga logo in front  of the fraction with a INF aboe th sigma and a n=0 below

anonymous · Answer

$$\sum_{n=0}^{INF}$$

thomas5267 · Answer

Find such x such that:
$$
\sum_{n=0}^\infty\frac{(x+8)^n}{2^n}=\infty
$$