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Chemistry 21 Online
OpenStudy (vera_ewing):

Chem

OpenStudy (vera_ewing):

@taramgrant0543664

OpenStudy (vera_ewing):

@JoannaBlackwelder

OpenStudy (taramgrant0543664):

I know at stp the most ideal would be O2 and the C2H4 but I'm not for sure when pressure is high

OpenStudy (vera_ewing):

Would the answer be D. C?

OpenStudy (joannablackwelder):

Have you studies van der waals equation and constants?

OpenStudy (vera_ewing):

Yeah a little bit.

OpenStudy (joannablackwelder):

Do you see a trend in the constants of these substances?

OpenStudy (vera_ewing):

Yes.

OpenStudy (joannablackwelder):

What trend do you see and what do you think it means?

OpenStudy (vera_ewing):

The bonds are decreasing from A to B? So I think that D. C would have ideal behavior at high pressures.

OpenStudy (joannablackwelder):

What do you mean that the bonds are decreasing?

OpenStudy (vera_ewing):

A has more bonds than B, C, and D.

OpenStudy (joannablackwelder):

That is true. Are you saying that oxygen gas will be most ideal at high pressures?

OpenStudy (vera_ewing):

Well I think Ne would have ideal behavior at high pressures. Or O-O. Am I correct?

OpenStudy (joannablackwelder):

Yes, I get one of those. Do you have the van der waals constants for each?

OpenStudy (vera_ewing):

No. But I think it's O-O, not Ne.

OpenStudy (joannablackwelder):

http://chemed.chem.purdue.edu/genchem/topicreview/bp/ch4/deviation5.html Why do you think it is O-O?

OpenStudy (vera_ewing):

I think because it has one bond...

OpenStudy (joannablackwelder):

Why does that make it more ideal at high pressures do you think?

OpenStudy (vera_ewing):

Maybe because the one bond makes it more stable and it's between O and O?

OpenStudy (joannablackwelder):

Hm, let's look at the constants for O2 and Ne and see if we can draw any conclusions.

OpenStudy (joannablackwelder):

What values of constants do you think would make the van der waals equation simplify down to the ideal gas law?

OpenStudy (vera_ewing):

I'm not really sure...

OpenStudy (joannablackwelder):

If the an^2/V^2 term went to 0, what do you think would happen to van der waals?

OpenStudy (vera_ewing):

I'm not sure. Can you please explain?

OpenStudy (joannablackwelder):

If that term went to zero, then van der waals would simplify to|dw:1438902988176:dw|

OpenStudy (vera_ewing):

Okay

OpenStudy (joannablackwelder):

And what if the nb term went to 0?

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