Question

Set up, but do not evaluate, the integral which gives the volume when the region bounded by the curves y = Ln(x), y = 2, and x = 1 is revolved around the line y = −2.

Answer 1

\[\pi \int\limits_{1}^{e^2} 4 - \ln(x)^2\]

Answer 2

okay so in know that, this would be the volume if it was spun around the x- axis just not sure what to do when its revolved around y = -2

Answer 3

@ganeshie8 @Hero @jim_thompson5910 any idea ?

Answer 4

yep yep i know what it looks like, i've graphed it