Question

HELP is anyone in connexus!!? geometry B and can help

Answer 1

i did that polygon similarity one you closed

Answer 2

@DanJS thank you Dan mind helping me again

Answer 3

sure

Answer 4

I need to find the value of x and y but im confused as to how

Answer 5

first thing i see is just to set up 2 pythagorean theorems, and solve for x and y

Answer 6

maybe, might be too much work

Answer 7

im just confused im not sure how to get it

Answer 8

Triangle ABC and Triangle BDC are similar, they both have 3 of the same angles

Answer 9

since both have a right angle and the same marked angle, so the third angle is the same

Answer 10

so you can do ratios of the sides like last prob

Answer 11

\[\frac{ AB }{ BD } = \frac{ BC }{ AC } = \frac{ BC }{ DC }\]

Answer 12

\[\frac{ 5 }{ 3 } = \frac{ y }{ x+4 } = \frac{ y }{ x }\]

Answer 13

You can solve that for x and y

Answer 14

can you show me how to?

Answer 15

yes kinda

Answer 16

Not gonna lie im a bit lost by that

Answer 17

sorry that is false, i messed up

Answer 18

oh lol okay

Answer 19

ok, i just used two pythagorean theorems, and got x = 9/4 and y=15/4

Answer 20

Solving

5^2 + y^2 = (4+x)^2
and
3^2 + x^2 = y^2

Answer 21

did it on my calculator, no work

Answer 22

Hmmm thank you dan :)

Answer 23

welcome

Answer 24

In a right triangle, if an altitude is drawn to the hypotenuse, then all three triangles are similar.

This is the situation with this problem.
Start with triangle ABC. Since angle ABC is a right angle, triangle ABC is a right triangle.
Segment BD is the altitude of triangle ABC drawn to the hypotenuse of triangle ABC.
That means that triangles ABC, ADB, and BDC are similar triangles.

Once you know the triangles are similar, then the lengths of corresponding sides are proportional, so you can write these two proportions:

\(\dfrac{AB}{BC} = \dfrac{AD}{BD} \) and \(\dfrac{AD}{BD} = \dfrac{BD}{DC} \)

Replacing all segments by their given lengths, x, and y, you get:

\(\dfrac{5}{y} = \dfrac{4}{3} \) and \(\dfrac{4}{3} = \dfrac{3}{x} \)

\(4y = 15\) \(4x = 9\)

\(y = \dfrac{15}{4} = 3.75\) \(x = \dfrac{9}{4} = 2.25\)