Question

Solve x2 − 3x = −8

Answer 1

@Michele_Laino

Answer 2

a ,b , c values are \[\huge\rm Ax^2+Bx+C=0\]
where
a =leading coefficient
b= leading coefficient
c= constant term
So we need to add 8 to both sides
\[\huge~\rm~ x^2 − 3x+8 \]
Now factor from here
What numbers multiply to make 8 but add to make -3? if there are none the answer would be prime

Answer 3

@ganeshie8 @Hero

Answer 4

?

Answer 5

idk what numbers multiply to 8 and add to -3

Answer 6

@pooja195

Answer 7

Then clearly there is not solution :) reread what i wrote are you given options?

Answer 8

no solution isnt an option

Answer 9

What are the options?

Answer 10

Um I don't know how to right them out

Answer 11

Just type them out

Answer 12

Or scrnshot

Answer 13

okay hold on

Answer 14

I havent learned "i" yet.... @UsukiDoll

Answer 15

Use the quadratic formula.

Answer 16

HUH?! O_O! that was random

Answer 17

yeah use quadratics on this equation...
use discriminant formula b^2-4ac to see if we have a perfect square or not
perfect square - we can factor
not a perfect square - use quadratic formula

Answer 18

wait what do i do?

Answer 19

\[\huge~\rm~ x^2 − 3x+8 \] where a = 1, b = -3, and c = 8
plug it into the discriminant formula which is b^2-4ac
\[\LARGE (-3)^2-4(1)(8) \]

Answer 20

okay what next?

Answer 21

\[\LARGE (-3)^2-4(1)(8) \]
\[\LARGE 9-32 = -23 \]
not a perfect square and a negative... ok looks like we're going to have complex roots.

Answer 22

now we solved the b^2-4ac already so that makes the quadratic formula a bit easier
\[\LARGE \frac{ -b \pm \sqrt{b^2-4ac}}{2a}\]

Answer 23

since a = 1, b = -3, and c = 8
\[\LARGE \frac{ -(-3) \pm \sqrt{-23}}{2}\]
negatives aren't allowed in the radical...so we write an i which stands for imaginary.
\[\LARGE \frac{ 3 \pm \sqrt{23}i}{2}\]

Answer 24

so the answer would be b?

Answer 25

wait... I haven't looked at that portion yet.

Answer 26

.docx hates me :(

Answer 27

okay ill try to get it on something else

Answer 28

finally got through to it.. it is the second choice.

Answer 29

Thank you!!!!