Question

Solve the triangle.

A = 50°, b = 13, c = 6

Answer 1

Yes I get that but how do I find my missing pieces

Answer 2

You can use the law of sines or cosines

Answer 3

I don't get how to do that I'm going virtual school and I need someone to walk me step by step

Answer 4

http://www.mathwarehouse.com/trigonometry/law-of-cosines-formula-examples.php

Answer 5

\[a^2 = 6^2 + 13^2 - 2(6)(13)*\cos(50)\]

Answer 6

I don't have a calculator except my phone so when I do it, I don't get any of my answer choices

Answer 7

you get side a from that one, then you can use law of sines to get the last 2 angles

\[\frac{ \sin(A) }{ a } = \frac{ \sin(B) }{ b } = \frac{ \sin(C) }{ c }\]

Answer 8

Is there anyway you can calculate that because my phone doesn't get me the correct answer

Answer 9

a^2 = 36 + 169 - 156*(0.6428)

a^2 = 104.7

a = about 10.2

Answer 10

\[\frac{ \sin(50) }{ 10.2 }=\frac{ \sin(B) }{ 13 }\]

Answer 11

B= about 77.5 degrees

Answer 12

THe last angle is 180 - the other 2