Question

will medal and fan!!!




A base of a parallelogram is on the x-axis and the origin is located at the left endpoint of that base. Three consecutive vertices are (h, j), (0, 0), and (k, 0), where h > 0.

How many units to the right of a vertical line through (k, 0) must the fourth vertex be?

h
2h
k + h

Answer 1

The x-axis and y-axis are lines of symmetry for a square. If one of its vertices has coordinates ( a, b), then the vertice opposite it is

( a, -b)
(- a, -b)
(- a, b)

Answer 2

The base of that parallelogram is from (0,0) to (k,0)

Answer 3

ok..

Answer 4

so what do i do now

Answer 5

(h, j ) is the upper left point from consecutive terms

To get the upper right point, you stay at the same y-coordinate, and move right the same length as the base, k units

Answer 6

i still nit understanding

Answer 7

not

Answer 8

would it be 2h? just asking

Answer 9

The base is k units long...
So the top must also be k units long

the y coordinate stays the same value