Question

Please help me I will give you metals

Answer 1

@phi

Answer 2

@dan815

Answer 3

@robtony

Answer 4

were you able to find dy/dx ?

Answer 5

yes, I have the prime derivative
I got -3x/y

Answer 6

correct

\[\Large \frac{dy}{dx} = \frac{-3x}{y}\]

Answer 7

Now apply the derivative to both sides

\[\Large \frac{dy}{dx} = \frac{-3x}{y}\]
\[\Large \frac{d}{dx}\left[\frac{dy}{dx}\right] = \frac{d}{dx}\left[\frac{-3x}{y}\right]\]
\[\Large \frac{d^2y}{dx^2} = ??\]

Answer 8

and then for the y'' i got
-3y-y'(-3x)
---------
4y^2

Answer 9

and then I plug -3x/y on the y' right?

Answer 10

correct and simplify

Answer 11

-3y+(9x/y)
----------
4y^2

Answer 12

I'm not getting the same thing

Answer 13

@jim_thompson5910 , from this pint do I just plug the values of x and Y?

Answer 14

what did you get?