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find f'(-3), if f(x)=(2x^2-7x)(-x^2-7). round your answer to the nearest integer
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just expand f(x) take derivative replace x =-3 in its derivative Done
ok but I end up with a really bigggggggggg number
Show your work, please
ok here: f(-3)=(2(-3)^2-7(-3))(-(-3)^2)) f(-3)=-624 I know I did something wrong
hey, your question is to find \(f'(-3)\) not \(f(-3)\)
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\(f(x) = (2x^2-7x)(-x^2-7)\) Use FOIL to expand it, what do you have?
-2x^4+49x
Nope |dw:1438996954403:dw|
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