A rocket is fired straight up from a 60 ft. platform with an initial velocity of 96 ft/sec. The heigh of the rocket, h(t), is found using the function h\left( t \right) = - 16{t^2} + 96t + 60 where t is the time in seconds.
Find the number of seconds required to reach the maximum height.

Question

A rocket is fired straight up from a 60 ft. platform with an initial velocity of 96 ft/sec.  The heigh of the rocket, h(t), is found using the function h\left( t \right) = - 16{t^2} + 96t + 60 where t is the time in seconds.
Find the number of seconds required to reach the maximum height.

irishboy123 · Answer

hint,

 at max height, $\large v(t)$ = 0 and $\large v(t) = \dot h(t) = \frac{dh}{dt} $

irishboy123 · Answer

or if that makes no sense to you, complete the square to find t at the peak of the parabola