An object of mass 2.00 kg is held at a position A, a vertical height of 20.0 m above the ground. Point B is 8.00 m directly below A. Neglect air resistance and use g = 10.0 m/s2.
What is the speed of the object at position B when it falls from position A?

I have no idea how to go about this...

Question

An object of mass 2.00 kg is held at a position A, a vertical height of 20.0 m above the ground. Point B is 8.00 m directly below A. Neglect air resistance and use g = 10.0 m/s2.
What is the speed of the object at position B when it falls from position A?

I have no idea how to go about this...

whpalmer4 · Answer

Find the time for the object to fall from position A to position B.  You can use $$x = \frac{1}{2}at^2$$to do so.  $x$ represents the distance traveled, $a$ is the acceleration (here due to gravity, so use the value provided for $g$), and $t$ is the time.  

When you have found the time required for the object to fall from position A to position B, you can use $$v = at$$ to calculate the speed. Again, $a=g$ and $t$ is the value you found in the first part.

anonymous · Answer

ok, thanks!!