Question

Find the particular solution to y ' = 2sin(x) given the general solution is y = C − 2cos(x) and the initial condition y(pi/2) = 0

−2cos(x)
2 − 2cos(x)
1 − 2cos(x)
−2 − 2cos(x)

Answer 1

not entirely sure what its even asking

Answer 2

i found c to equal 1 so im assuming its c but not entirely sure

Answer 3

sounds like it

Answer 4

its asking you to find c then replace the equation

Answer 5

with the actual c

Answer 6

okay got it, so then the answer is 1 − 2cos(x) right?

Answer 7

yes

Answer 8

thank you