Question

Which equation could be used to solve this problem?



The sum of two consecutive integers is 141. Find the integers.



A.


n + 1= 141


B.


2n + 2 = 141


C.


2n = 141


D.


2n + 1 = 141

Answer 1

@Michele_Laino

Answer 2

i'm thinking D @Michele_Laino

Answer 3

@Haseeb96

Answer 4

if n is an integer, then its consecutive is n+1, so we can write this:
\[\Large n + \left( {n + 1} \right) = 141\]
please simplify

Answer 5

then A

Answer 6

no, since you have to compute this sum:
\[\Large n + \left( {n + 1} \right)\]

Answer 7

then has to be C

Answer 8

sorry, C) can't be the right option.
Hint:
\[\Large n + \left( {n + 1} \right) = n + n + 1\]

Answer 9

BBBBBBBBBB

Answer 10

no, since we have 1 not 2

Answer 11

whaaaaat. then its D

Answer 12

yes! it is D, we can write this:
\[\Large n + \left( {n + 1} \right) = n + n + 1 = 2n + 1 = 141\]

Answer 13

i was thinking D if you read my 2nd comment but thank you @Michele_Laino . :)

Answer 14

sorry!

Answer 15

np. >,<

Answer 16

:)