Question

Lara tossed a fair coin 3 times. What is the probability of getting heads in the first two trials?

1 over 8
2 over 8
3 over 8
4 over 8

will fan and medal

Answer 1

Okay, this might not make sense NOW, but it will later. Independent events are events that don't influence one another, and the probability of both happening is simply the product of their respective probabilities.

Answer 2

There, I said it

Answer 3

Now let's begin.

with just one coin toss, what's the probability of getting heads? :D

Answer 4

um idk

Answer 5

Really? C'mon, at least give it a guess :)

Answer 6

If it's easier to understand, what are the chances that you get heads with one toss?

Answer 7

i honestly do not know

Answer 8

Half. Fifty percent.
1/2
^^

Answer 9

Now, the second coin toss would be the same, half or 50% chance of getting heads, yes?

Answer 10

yes

Answer 11

Are the first and second coin tosses independent of each other?

Answer 12

no..?

Answer 13

coins dont have memory

Answer 14

in other words... does the result of the second coin toss depend on the result of the first one?

Answer 15

yes

Answer 16

idk

Answer 17

as if the coin remembers what happened in the previous toss and change its mind to flip the other side in next toss

that can never happen

Answer 18

can i just get the answer

Answer 19

if you just blindly guess the answer, you will get it correct with a probability of 1/4 because there are 4 options

Answer 20

is the answer 2/8 ?

Answer 21

Which is a coincidence XD

Answer 22

so 2/8 is the answer?

Answer 23

Haha your luck is at its best today!

Answer 24

yay lol

Answer 25

can you help me with some more problems

Answer 26

?

Answer 27

\[\frac{2}{8}?\]

Answer 28

\[\frac{1}{2}\times \frac{1}{2}=\frac{1}{4}\] which is in fact \(\frac{2}{8}\) but not what you want as a final answer

Answer 29

oh

Answer 30

so does anybody know the answer

Answer 31

2/8 is correct

Answer 32

At a game booth, a student gets a box of candy as the prize for winning a game. The boxes come in four colors: white, red, green, and blue. There are 10 boxes of each color. All the boxes are equally likely to be given away as prizes. Which expression shows the probability of the first winner receiving a white box and the second winner also receiving a box of the same color?

10 over 40 multiplied by 9 over 39
10 over 40 multiplied by 10 over 39
10 over 40 plus 9 over 39
10 over 40 plus 10 over 39

Answer 33

Alright, read the question and see if you can tell me what we need to find out exactly

Answer 34

2/8 is silly

Answer 35

Haha not more sillier than 200/800

I think the teacher wants the kids to solve it by listing out all the possibilities and pick the favorable ones

Answer 36

rational numbers trip all kids in the start because they have infinitely many representations :

(2, 8) = (1, 4) = (4, 16) = ...

Answer 37

thats why i hate them :)

Answer 38

hehe forgetting all sentimental attachment to certain box colours, the colour of the candy boxes given away to separate winners don't affect each other, right?

IE... they're indpendent? ;)

Answer 39

ok

Answer 40

Okay, so this is a bit of a stretch, so I'm going to lay it out for you.
In general, probability is:

number of desirable outcomes
divided by
total number of possible outcomes.

With forty boxes and ten white boxes, what's the probability of getting a white box?

Answer 41

idk

Answer 42

\[\Large \frac{\text{number of desired outcomes}}{\text{total number of outcomes}}\]
how about now?

Answer 43

still dont know

Answer 44

Give it your best guess? I bet the choices give you some kind of clue ^^

Answer 45

Why don't we try process elimination? C and D seem silly.

Answer 46

lol yes, let's :D

My professors were evil with these multiple choice questions, having the correct answer and the deceptively similar common mistakes among the choices

o.O

Answer 47

Lmao. ^-^

Answer 48

@Skielerlucas04 are you still mad at me