Question

FAN AND MEDAL

Amir pitches a baseball at an initial height of 6 feet, with a velocity of 73 feet per second. If the batter misses, about how long does it take the ball hit the ground?

Hint: Use H(t) = −16t^2 + vt + s.

4.64 seconds
2.94 seconds
2.28 seconds
0.08 second

Answer 1

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Answer 2

@hartnn help please!

Answer 3

just plug in the values given in the equation,
H(t) = −16t^2 + vt + s.

here
s= initial height = 6
v = velocity = 73
and the height at ground level H(t) = 0

only 't' is unknown!

Answer 4

you'll get a quadratic in 't'
let me know if you have any doubts in solving that?

Answer 5

how do i find t?

Answer 6

did u plug in values?
what did u get?

Answer 7

-16t^2+73t+6=0

Answer 8

now use quadratic formula to solve that!

Answer 9

Compare your quadratic equation with \(ax^2+bx+c=0\)
find \[a=...?\\b=...?\\c=...?\\\] \[ \\ \sqrt{b^2-4ac}=...?\]
then the two roots of x are:

\(\huge{x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)

Answer 10

oh ok can you wait for me to solve it?

Answer 11

don't tag me anymore

Answer 12

sure, just gave you the steps :)

Answer 13

y? @triciaal

Answer 14

alright I'm almost done

Answer 15

is it 4.64? @hartnn

Answer 16

yes! correct :)

Answer 17

thank you!!

Answer 18

welcome ^_^