Question

An object has a constant acceleration of 40 ft/sec2, an initial velocity of −20 ft/sec, and an initial position of 10 ft. Find the position function, s(t), describing the motion of the object.
Please help ill give medal

Answer 1

Do you remember the general position function?

Answer 2

d(t)= integral v(t)dt= double integral a(t)?

Answer 3

That's true but it only helps if you know one of those equations. The position function is:
\[x _{0}+(dx/dt)t+(1/2)(d ^{2}x/dt ^{2})t ^{2}\]
Or as you probably like to remember it:
\[x _{0}+vt+\frac{ at ^{2} }{ 2 }\]

Answer 4

But do keep in mind what you said too. It saves you the trouble of blindly memorizing three equations, and so you only need one of them to get the other two.

Answer 5

Do you know what to do now? Because from here you just need to plug it in

Answer 6

Not sure what to plug in

Answer 7

just confused on the steps on how to solve the problem

Answer 8

x0 is the initial position. v is the initial velocity (in retrospect I forgot to write v0 to be consistent). a is the acceleration. And t is time.

Answer 9

I think you just need to set up the equation and leave t as is

Answer 10

oh ok thank you

Answer 11

so what would s(t) be or look like?

Answer 12

would it be 10+ (-20)=40(t)^2/2?