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OpenStudy (mathmath333):
\(\large \color{black}{\begin{align}
& \normalsize \text{In how many ways can the letters of the word PERMUTATIONS be arranged if the}\hspace{.33em}\\~\\
& \normalsize \text{ (i) vowels are all together }\hspace{.33em}\\~\\
& \normalsize \text{ (ii) there are always 4 letters between P and S.}\hspace{.33em}\\~\\
\end{align}}\)
OpenStudy (rational):
How many vowels are there ?
OpenStudy (mathmath333):
all vowels are there
OpenStudy (rational):
put them in a bag and call it \(\phi\)
OpenStudy (rational):
how many ways can arrange the objects \(\{\phi, ~P, ~R, ~M,~T,~T,~N,~S\}\) ?
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OpenStudy (mathmath333):
=(8/2)!
OpenStudy (anonymous):
12!/(12-5)! for i?
OpenStudy (rational):
you mean 8!/2 ?
OpenStudy (mathmath333):
ya this one
OpenStudy (rational):
Yes, next unpack the bag, how many ways can you arrange 5 vowels ?
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OpenStudy (mathmath333):
can vowels be repeated
OpenStudy (rational):
what letters do you have in the bag ?
OpenStudy (mathmath333):
aeiou
OpenStudy (rational):
they all are distinct, how many ways can you arrange them ?
OpenStudy (mathmath333):
5!
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OpenStudy (rational):
Yes, so the final answer is ?
OpenStudy (mathmath333):
8!*5!/2
OpenStudy (rational):
looks good!
OpenStudy (mathmath333):
ok the next one
OpenStudy (ikram002p):
separated than the first condition ?
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OpenStudy (mathmath333):
P and S are at distance of 4 places always
OpenStudy (rational):
First find the number of ways of placing \(P, S\) :
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