Question

sectheta - costheta / sintheta

Answer 1

write sec theta in terms of sin,cos
sec theta = what ?
do you know ?

Answer 2

yeS or n0 ?

Answer 3

no :)

Answer 4

one would note there isn't really a questoin, just a statement

Answer 5

what does sec equal to ?

Answer 6

or in other words do you know the definition of sec theta ?

Answer 7

Write in terms of sin and cosine and simplify

Answer 8

did you read my comments ? I want to know how much you already know abt trig

Answer 9

^ :D

Answer 10

Not much at all am taking it this semester just trying to get a head start

Answer 11

thanks thank you!!! \[\rm \sin \theta = \frac{ 1 }{ \csc \theta }\]\[\cos \theta =\frac{ 1 }{ \sec \theta }\]\[\tan \theta=\frac{ 1 }{ \cot \theta } = \frac{ \sin \theta }{ \cos \theta }\]
these are the definition of sin,cos and tan
cos is reciprocal of sec

Answer 12

so you can replace sec with 1/cos \[\huge\rm \frac{ \color{reD}{\sec} \theta -\cos \theta }{ \sin \theta }\] \[\huge\rm \frac{ \frac{ 1 }{ \cos \theta } -\cos \theta }{ \sin \theta }\]
now find the common denominator of \[\frac{ 1 }{ \cos \theta }-\cos \theta \]

Answer 13

Thanks

Answer 14

no done yet.

Answer 15

not*

Answer 16

can you solve that from there ?

Answer 17

Would be appreciated if you can finish it

Answer 18

well,hm
common denominator is cos \[\frac{ \frac{ 1-\cos^ 2 \theta }{ \cos }}{ \sin \theta }\]
so multiply both terms by cos
1/cos times cos and cos times cos
when you multiply same bases you should add their exponents
so cos times cos = cos^2
and 1/cos times cos =1
tthat's how you get 1 -cos^2 theta

Answer 19

now you must know this special identity \[\huge\rm sin^2 \theta+\cos^2 \theta =1\] solve this equation for sin^2 theta
let me know what you get