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OpenStudy (anonymous):

A solution is made by dissolving 4.0 moles of sodium chloride (NaCl) in 2.05 kilograms of water. If the molal boiling point constant for water (Kb) is 0.51 °C/m, what would be the boiling point of this solution? Show all of the work needed to solve this problem

OpenStudy (anonymous):

@Photon336 please help

OpenStudy (anonymous):

@abb0t

OpenStudy (taramgrant0543664):

So our first step is to determine how many moles of NaOH we have per kilogram of water m=4.0 moles/2.05kg m=?

OpenStudy (taramgrant0543664):

@lovingod786 ??

OpenStudy (anonymous):

Sorry Im here

OpenStudy (anonymous):

@taramgrant0543664

OpenStudy (anonymous):

1.95 kg?

OpenStudy (taramgrant0543664):

Yes it would be 1.95 but it would be moles/kg

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

then what

OpenStudy (taramgrant0543664):

So our next step is to find our van't Hoff factor which is represented by i

OpenStudy (anonymous):

que? Mind speaking english lol

OpenStudy (taramgrant0543664):

This factor is a constant associated with the dissociation of the solute in the solvent

OpenStudy (taramgrant0543664):

So NaCl breaks down into two ions Na+ and Cl- meaning that our i value is 2 (keep in mind that it changes for each reaction)

OpenStudy (anonymous):

ok

OpenStudy (taramgrant0543664):

Last step now! We have a formula which is T=iKbm T is your change in temperature, i is 2 as found in second step, Kb is given 0.51 and m is what we found in the first step

OpenStudy (anonymous):

ok so T= (2)(0.51)(1.95) = 1.989 mol/kg yes?

OpenStudy (taramgrant0543664):

Yes so the change in temperature is 1.989 (note it's not in mol/kg anymore it is degrees celcius now) to find the boiling point you add this number to the boiling point of water

OpenStudy (anonymous):

so 1.989 + 0.51?

OpenStudy (taramgrant0543664):

The boiling point for water is 100 C so you would add that to the 1.989 the 0.51 is just a constant. For boiling point with water involved you add to 100. If you are doing freezing point with water then you would subtract from zero since 0 is the freezing point.

OpenStudy (anonymous):

so 109.989

OpenStudy (taramgrant0543664):

101.989 celcius would be the boiling point

OpenStudy (anonymous):

So thats the answer?

OpenStudy (taramgrant0543664):

Yes that would be your answer for the boiling point

OpenStudy (anonymous):

ok thx

OpenStudy (anonymous):

i got another question would you like to help

OpenStudy (taramgrant0543664):

Of course I can help, start a new post though so I can find everything easier please!

OpenStudy (anonymous):

ok

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