Question

Expand the logarithmic expression.
log7(n/5)

Answer 1

quotient rule\[\large\rm log_b y - \log_b x = \log_b \frac{ x }{ y}\]
to condense you can change subtraction to division
product rule \[\large\rm log_b x + \log_b y = \log_b( x \times y )\]
addition ----> multiplication

power rule \[\large\rm log_b x^y = y \log_b x\]

Answer 2

\[\huge\rm log_7 \frac{ n }{ 5}\]which property you should apply ?

Answer 3

quotient rule

Answer 4

yes!

Answer 5

yep right
btw 7 is base right ?

Answer 6

yes 7 is the base

Answer 7

alright

Answer 8

so how would you expand that ?

Answer 9

log7(5)-log5(n)

Answer 10

hmm log5(n) ??

Answer 11

oh, i meant 7

Answer 12

we need to have the same base value... 99% sure that's a typo

Answer 13

right :=)

Answer 14

it was a typo, thanks to both of you!

Answer 15

pleasure.

Answer 16

I think it's backwards though.
with the quotient rule wouldn't it be \[\log_7(n)-\log_7(5)\]

Answer 17

are you sure? 5 was the denominator

Answer 18

ohh yeah i thought n is the denominator

Answer 19

-_- I saw
log7(5)-log7(n) that's 5/n not n/5

Answer 20

nvm arnv my bad
i typed that wrong in the properties

Answer 21

oh, don't worry about it, thank you guys again!

Answer 22

thanks! i'll write it correctly

Answer 23

\(\color{blue}{\text{Originally Posted by}}\) @Nnesha
quotient rule\[\large\rm log_b y - \log_b x = \log_b \frac{ x }{ y}\]
to condense you can change subtraction to division
product rule \[\large\rm log_b x + \log_b y = \log_b( x \times y )\]
addition ----> multiplication

power rule \[\large\rm log_b x^y = y \log_b x\]
\(\color{blue}{\text{End of Quote}}\)


correction quotient rule\[\large\rm log_b x - \log_b y = \log_b \frac{ x }{ y}\]
to condense you can change subtraction to division
product rule \[\large\rm log_b x + \log_b y = \log_b( x \times y )\]
addition ----> multiplication

power rule \[\large\rm log_b x^y = y \log_b x\]

Answer 24

looks right ;)