Question

Questions

Attached

Answer 1

where?

Answer 2

Attached

Answer 3

Here

Answer 4

Here too

Answer 5

@rushwr @sweetburger

Answer 6

When stating an answer please provide a justification as to why you got the answer and why you feel the others are wrong.

Answer 7

for 381. I will go with C. Because we know when it says a reaction is non spontaneous \[DeltaG > 0\]

Answer 8

since they have not mentioned anything about a heat change or anything we can't predict anything about enthalpy and entropy soo those answers are cut off

Answer 9

the last one happens when the reaction is in equilibrium !

Answer 10

381. C

\[\Delta G = \Delta H - T \Delta S \]

The spontaneity of a reaction does not dictate how fast the reaction will go but rather the tendency of that reaction to occur. if something is spontaneous/ a reaction it will happen.
because there is free energy. delta G shows us the free energy available.

These three answers below are wrong because, you need two know both the sign of delta H and Delta T S to determine whether a reaction is spontaneous.

delta S = negative wrong
Delta H is positive wrong
Delta G = 0

Delta G = 0 means that it's neither spontaneous in the forward or reverse direction.

Delta G must be greater than zero, that would mean that the reaction is spontaneous in the opposite direction not the forward direction.

Answer 11

When ΔG is negative, a process or chemical reaction proceeds spontaneously in the forward direction.
When ΔG is positive, the process proceeds spontaneously in reverse.
When ΔG is zero, the process is already in equilibrium, with no net change taking place over time.

Answer 12

382. I'll go with D. STP is know as the standard conditions . But here it says it's not the same so wrong !

Answer 13

hey what is delta Hrxn? Is it the enthalpy for the reverse reaction ?

Answer 14

Hrxn is the enthalpy of reaction

Answer 15

Standard enthalpy of formation is the change that occurs when one mole of a compound is formed from its constituents in their most abundant allotropes and naturally existing physical states under standard conditions for a compound. Since there is 2 moles of HF formed the enthalpy value should be multiplyed by 2 making it the answer A

Answer 16

382. B



can clearly see why A is correct.
B cooling to absolute zero would imply that the molecules just stop moving,
at absolute zero so that's true.

C STP = Standard temperature and pressure 1 atm 25C correct.
D is correct, elements yeah the standard Heat of enthalpy is zero because they just aren't formed from anything, well at least fro enthalpy.