here, a question .please help
let V be the space of polynomial over R \[\le2\]
.let \[\emptyset _{1} \emptyset _{2} \emptyset _{3}\] be the linear functional on V defiend by
\[\emptyset _{1}(f(t))=f(t)dt,\emptyset _{2}f(t)=f \prime (1),\emptyset _{3}(f(t))=f(0). here f(t)=a+bt+ct^2\] and f'(t) denots the derivative of f(t).
find the basis {\[f _{1}(t),f _{2}(t),f _{3}(t)\] of V that is dual to \[ \emptyset _{1}, \emptyset _{2}, \emptyset _{3},\]
please help
@zzr0ck3r
@oldrin.bataku
@Loser66
@Michele_Laino
@Kainui
@oldrin.bataku
Can you tell me what a basis, functional, and what do you mean by spaces, and over R. If you ant answer all four of those questions, you should read up before trying this.
@jtvatsim
OK, so I noticed that zzr0ck3r had some questions for you. Were you clear on those definitions?
Phew... that was tough. I hope it isn't so tough reading it. Take your time through it. Ultimately, dual just means that you will be setting equations equal to 0s and 1. It's a simple idea, but very hard to get across. Good luck! I'm signing off for tonight. :)
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