Question

Question

Answer 1

388/389

Answer 2

386/387

Answer 3

@taramgrant0543664 @Rushwr @sweetburger @Woodward

Answer 4

388 @rushwr?

Answer 5

thinking

Answer 6

\[Ca _{s} + Cl _{2g} \rightarrow CaCl _{2s}\]

Answer 7

is it B?

Answer 8

cuz the reaction is a formation reaction hence it is an exothermic reaction. SO delta H is negative

Answer 9

\[\Delta S _{surr} =\frac{ -\Delta H }{ T }\]

Answer 10

\[\Delta G = \Delta H - T \Delta S \]

so for our reaction the entropy would have to go down.
so the sign TDeltaS would be positive.

that means that for our reaction, which we know is spontaneous because we form our reactants. Delta G < 0

if we put the two together.

1. Delta G <0
2. Entropy Delta S < 0
3. TdeltaS > 0

THIS means that T delta S would be > 0 positive.
and Delta G < 0

therefore the enthalpy Delta H would have to be large and negative, to offset the positive entropy and that would make delta G < 0

Answer 11

sorry form our products***

Answer 12

389. A Cuz when they had more reactants in to the system the system tend to attain the equilibrium by making more products. So the euilibrium points shifts to the left forming more products.

Answer 13

\[\Delta G = \Delta H - T \Delta S \]

True entropy is \[\Delta S = \frac{ -\Delta H }{ T }\]

because we end up with solid calcium chloride (s) we know overall the entropy goes down.
so in that equation. delta S < 0

\[\Delta S < 0 \]

\[\Delta H < 0 \]

Answer 14

389 is so tricky the first time I did it i got it wrong

Answer 15

@taramgrant0543664 thoughts for 389?

Answer 16

what's the answer given for 389. I explained one !

Answer 17

So I was thinking at first A until I saw that it was in solid form solids don't change rate so I was considering c

Answer 18

@Rushwr it's C no change

Answer 19

oh yes it doesn't count for the K values yes. u are right!

Answer 20

equilibrium expressions, the K value(s) i think it's pure liquids and solids aren't included.

Answer 21

I didn't see the states properly ! Thank you @taramgrant0543664 and @Photon336

Answer 22

For it to be counted it's either in gas or aqueous form

Answer 23

@taramgrant0543664 I love you!

Answer 24

Definitely watch those states that's the thing that always gets me lol

Answer 25

\[Keq = [Cl _{2}] \]

\[K _{eq} = \frac{ [C][D] }{ [A][B] }\]

Answer 26

yeah... that one got me too..

Answer 27

Was the answer for 388 said? I might have missed that I know I missed part of your conversation since I got tagged in the math section

Answer 28

it remains the same because the Keq depends only on the concentration of the gas chlorine.

Answer 29

so it's C

Answer 30

Right I was thinking that but thought I would double check as sometimes I am completely off on them lol what's the next one?

Answer 31

387. A. because like replacing a strong acid with a weak one in that reaction would cause the temperature change to rise to a smaller degree, and the enthalpy change would be less.

Answer 32

I just gave an answer for 387, so all that's left is 386

Answer 33

I will post one more set of questions then I g2g

Answer 34

okai !

Answer 35

Btw Thanks alot @Photon336

Answer 36

386 I missed that one

Answer 37

These are kind of fun to do @Photon336!!
As for 386 I was considering D as my option possibly?

Answer 38

IKR this is awesome ! @taramgrant0543664 @Photon336

Answer 39

Yeah it's D.

Answer 40

ok Will post one more.