Reasoning question

Question

Reasoning question

mathmath333 · Answer

$\large \color{black}{\begin{align} 
& \normalsize \text{Find the odd man out}\hspace{.33em}\~\
& a.)\ 324 \hspace{.33em}\~\
& b.)\ 244 \hspace{.33em}\~\
& c.)\ 514 \hspace{.33em}\~\
& d.)\ 136 \hspace{.33em}\~\
\end{align}}$

mathmath333 · Answer

$324=2^{2}\times 3^{4}\
224=2^{2}\times 61\
514=2^{3}\times 257\
136=2^{3}\times 3^{4}$

ganeshie8 · Answer

Hint : sum of digits

mathmath333 · Answer

sum of digits 
$324\rightarrow 9\
224\rightarrow 8\
514\rightarrow 10\
136\rightarrow 10$

anonymous · Answer

Using sum of digits, a) is the odd man out.
Also, d) is odd man out considering the one's digit.

mathmath333 · Answer

d.) correct ?

anonymous · Answer

@mathmath333 , there's something wrong with your prime factorizations. And the second number is 244, not 224.

amilapsn · Answer

b) too @ospreytriple because its first digit isn't odd!

mathmath333 · Answer

this  one

$324=2^{2}\times 3^{4}\
244=2^{2}\times 61\
514=2\times 257\
136=2^{3}\times 3^{4}$

anonymous · Answer

@mathmath333 , $136 = 2^3 \times 17$

mathmath333 · Answer

ok

thomas5267 · Answer

It could be argued that 514 is the odd one as its prime factorisation contains only two primes.  Or even the answer is none of above as all of the options are numbers not man.