Question

im getting x=-6 is that correct? @Nnesha @madhu.mukherjee.946 @mathstudent55

Answer 1

how did you get -6 ?

Answer 2

im not entirely sure im still half asleep

Answer 3

show ur work.
same like the last one
1st) take square both sides

Answer 4

\[\huge\rm ( \sqrt{-3x-2})^2=(x+2)^2\] when you take square on left side square root would cancel out \[\huge\rm -3x-2=(x+2)^2\]
now solve for x
(x+2)^2 is same as (x+2)(x+2) apply the foil method

Answer 5

\[-3x -2=(x+2)^2 \]

Answer 6

x=-6, -1

Answer 7

hmm

Answer 8

-1 works as a solution and so does -6 how am i still getting these

Answer 9

yes so answer is what ?

Answer 10

i don't know I'm so confused right now

Answer 11

\(\color{blue}{\text{Originally Posted by}}\) @purplemexican
-1 works as a solution and so does -6 how am i still getting these
\(\color{blue}{\text{End of Quote}}\)
okay substitute x for -6

Answer 12

\[\sqrt{-3(-6)-2}=-6x+2\] both sides are e qual ?

Answer 13

thats where i messed up

Answer 14

i did -3(-6)-2=(-6+2)^2

Answer 15

no don't take square root on right side

Answer 16

we need to plug in -6 into the original equation :=)

Answer 17

\(\color{blue}{\text{Originally Posted by}}\) @Nnesha
\[\sqrt{-3(-6)-2}=-6x+2\] both sides are e qual ?
\(\color{blue}{\text{End of Quote}}\)
correction \[\sqrt{-3(-6)-2}=-6+2\] both sides are e qual ?

Answer 18

1sT) multiply -3 times -6
2nd) subtract -2
take square root of that number

Answer 19

4

Answer 20

okay so 4=-6+2 both sides are equal ?

Answer 21

no

Answer 22

so that's an extraneous solution

Answer 23

thank you again

Answer 24

my pleasure.
good job!