Question

chem question

Answer 1

did use this equation? \[\Delta G = -RTK _{eq}\]

Answer 2

how did u get that?

Answer 3

show me ur work

Answer 4

@Photon336

Answer 5

ah yes

Answer 6

you need to use \[\Delta G = -RTlnKc\]

Answer 7

Kc = 54.8
450 C + 273 = 723 K
R = 0.008314 Kj/K*mol

plug these all in but let me double check the units first.

Answer 8

Vera_ewing let me check this first

Answer 9

we know that our Kc > 1 so our delta G must be negative from our equation.

I think it's -24.1 kj/mol

Answer 10

\[-(723K)(0.008314Kj/mol)Ln(54.3) \]