The average kinetic energy of 1 mole of a gas at -32 degrees Celsius is:

3.01 x 103 J

3.99 x 102 J

-3.99 x 102 J

3.80 x 103 J

Question

The average kinetic energy of 1 mole of a gas at -32 degrees Celsius is:
 	
	
3.01 x 103 J
	
3.99 x 102 J
	
-3.99 x 102 J
	
3.80 x 103 J

taramgrant0543664 · Answer

KE=(3/2)nRT
Where KE is kinetic energy
n is number of moles
R is 8.31J/K
T is temperature in Kelvin

mmend98 · Answer

What is the final answer? its okay this isn't a test. ill give u a medal lol @taramgrant0543664

taramgrant0543664 · Answer

KE=(3/2)(1.0)(8.31)(-32+273)
KE=3004J
KE=3.00x10^3J

taramgrant0543664 · Answer

If you use 273.15 then KE=3005 so rounding that to three significant digits it would be 3010 making it 3.01x10^3 in scientific notation