Question

Calculate the discriminant and use it to determine how many real-number roots the equation has.



3x2 – 6x + 3 = 0



A.
no real-number roots


B.
two real-number roots


C.
three real-number roots


D.
one real-number root

Answer 1

@happyrosy

Answer 2

@Michele_Laino @peachpi

Answer 3

@Mehek14

Answer 4

you dont have to help me i know the stuff i think i have the answer C

Answer 5

Alright, same way as before a=3, b=-6, and c=3
(-6)^2-4(3)(3)=36-36=0
Okay, the rule with dsicriminants is:
If > 0: There are two real roots
If = 0: There is one real root
If < 0: There are two complex roots

Answer 6

The main reason it cannot be C is because the equation is a to the power of two meaning at most, it can only have 2 roots.

Answer 7

D

Answer 8

D is correct

Answer 9

thank you

Answer 10

Mhm