Question

Find a cubic function with the given zeros:
7, -3, 2

Answer 1

options for answer: f(x) = x3 - 6x2 - 13x - 42
f(x) = x3 - 6x2 + 13x + 42
f(x) = x3 - 6x2 - 13x + 42
f(x) = x3 + 6x2 - 13 + 42

Answer 2

If \(a\) is a root of a polynomial \(P(x)\), then \((x-a)\) divides \(P(x)\)
Here we need a polynomial with roots 7, -3, 2
The simplest polynomial that we can think of with these roots is
\[(x-7)(x-(-3))(x-2)\] that is \((x-7)(x+3)(x-2)\)
Multiply it out to get the result.

Answer 3

oh okay thanks