A box has 8 beads of the same size, but all are different colors. Tamy draws a bead randomly from the box, notes its color, and then puts the bead back in the box. She repeats this 3 times. What is the probability that Tamy would pick a red bead on the first draw, then a white bead, and finally a red bead again?

Answers are 1/4096 1/512 1/64 and 1/8 its not i1/8 cause I tried it and got it wrong so I though it would be 1/64? :)

Question

A box has 8 beads of the same size, but all are different colors. Tamy draws a bead randomly from the box, notes its color, and then puts the bead back in the box. She repeats this 3 times. What is the probability that Tamy would pick a red bead on the first draw, then a white bead, and finally a red bead again?

Answers are 1/4096 1/512 1/64 and 1/8 its not i1/8 cause I tried it and got it wrong so I though it would be 1/64? :)

anonymous · Answer

Hell o again

kropot72 · Answer

The probability of drawing any one of the colors is 1/8. The results of each draw are independent. Therefore the required probability is
$$\large \frac{1}{8}\times\frac{1}{8}\times\frac{1}{8}=you\ can\ calculate$$

anonymous · Answer

hi. so it's 1/8 for each draw since the beads are being replaced. Then you need to multiply them to get the probability
$$\frac{ 1 }{ 8 }\times \frac{ 1 }{ 8 }\times \frac{ 1 }{ 8 }$$

anonymous · Answer

oh I got it thank you guys so much