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OpenStudy (wampominater):
Determine two pairs of polar coordinates for the point (4, -4) with 0° ≤ θ < 360°.
11 years ago
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OpenStudy (wampominater):
so right now I have \[\cos(\theta) = \frac{ 4 }{ 4\sqrt{2} }\] and \[\sin(\theta)=-\frac{ 4 }{ 4\sqrt{2} }\] but i dont know where to go from here... please help!
11 years ago
jimthompson5910 (jim_thompson5910):
the 4's cancel leaving with 1 over sqrt(2) for the first fraction
11 years ago
jimthompson5910 (jim_thompson5910):
\[\Large \frac{1}{\sqrt{2}} = \frac{\sqrt{2}}{2}\]
11 years ago
OpenStudy (wampominater):
alright, but how do i make that a polar coordinate. i need to take the arc sin according to the examples in my book but that doesnt work here
11 years ago
OpenStudy (wampominater):
and the arc cos
11 years ago
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jimthompson5910 (jim_thompson5910):
you can use the unit circle
11 years ago
OpenStudy (wampominater):
oh wait cause now they are known values on the unit circle
11 years ago
jimthompson5910 (jim_thompson5910):
look on the unit circle where the x coordinate is \(\Large \frac{1}{\sqrt{2}}\) or \(\Large \frac{\sqrt{2}}{2}\)
11 years ago
OpenStudy (wampominater):
315
11 years ago
OpenStudy (wampominater):
ok so the first polar coordinate would be \[\left( 4\sqrt{2} , 315\right)\]
11 years ago
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jimthompson5910 (jim_thompson5910):
yes
11 years ago
OpenStudy (wampominater):
how would i find a second one equal to that?
11 years ago
jimthompson5910 (jim_thompson5910):
|dw:1439180139138:dw|
11 years ago
jimthompson5910 (jim_thompson5910):
|dw:1439180155156:dw|
11 years ago
jimthompson5910 (jim_thompson5910):
Draw a line from (4,-4) through the origin
|dw:1439180192858:dw|
11 years ago
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jimthompson5910 (jim_thompson5910):
|dw:1439180205002:dw|
11 years ago
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