Question

On the Moon, a falling object falls just 2.65 feet in the first second after being dropped. Each second it falls 5.3 feet farther than in the previous second. How far would an object fall in the first ten seconds after being dropped?

Answer 1

this is a an arithmetic series where the first term is 2.65 and each subsequent term is obtained by adding the common difference 35.

Answer 2

a.
270 ft
c.
313 ft
b.
692 ft
d.
265 ft

Answer 3

nth term = a1 + ( n- 1)d where a1 = first term , n = number of terms and d = common difference

so tenth term = 2.65 + 9*5.3

(common difference = 5.3 NOT 35 as i said in my first post)

Answer 4

so in the second second it traveled 2.65 + 5.3 = 7.95 feet

the total distance = sum of n terms = (n/2)[ a1 + L) where L = 10th term

so plug in the values of a1 , n (=10) , and L and work it out

Answer 5

what the formula

Answer 6

i've just given it

Answer 7

im confused please state it again if you don't mind

Answer 8

plug in a1 = 2.65 , n = 10 and L = 10th term = 2.65 + 9*5.3 = 50.35

Answer 9

so L=50.35 correct?

Answer 10

thats the distance travelled in the 10 th second . You want the total distance travelled after 10 seconds have passed
Use the formula to work that out.

Answer 11

Total distance = (n/2) * [a1 + L)

Answer 12

work ouy n/2 first then a1 + L then multiply the 2 results

Answer 13

i get 265

Answer 14

that's right

Answer 15

thank you

Answer 16

yw